This is the seventh in a series of posts on Fibonacci trigonometry:
Part 1: Basic Definitions
Part 2: The Canonical Basis and Closed-Form Expressions
Part 3: The Basic Analogies
Part 4: Fibonacci Formulas Using sinh, etc. — Real Number Version
Part 5: Fibonacci Formulas Using sinh, etc. — Complex Number Version
Part 6: Trigonometric-Style Identities
Part 7: The Fibonacci Tangent and Cotangent Functions
Part 8: Recurrence Relations for Ftan and Fcot
Recall that, since F behaves analogously to the sine function, and L to the cosine function, we followed the usual development of trigonometry by defining:
Ftan(n) = F(n) / L(n), the Fibonacci tangent functionFcot(n) = L(n) / F(n), the Fibonacci cotangent function (for n ≠ 0)Fsec(n) = 1 / L(n), the Fibonacci secant functionFcsc(n) = 1 / F(n), the Fibonacci cosecant function (for n ≠ 0)
We'll continue to use the notation F and L, since those symbols are standard, rather than using Fsin and Fcos, respectively.
Just as
- 1 – 5 Ftan(x)2 = 4 (–1)x Fsec(x)2
- Fcot(x)2 – 5 = 4 (–1)x Fcsc(x)2, for x ≠ 0
Ftan and Fcot are odd functions:
- Ftan(–x) = –Ftan(x)
- Fcot(–x) = –Fcot(x), for x ≠ 0
Fsec and Fcsc have the same opposite-sign properties as L and F:
- Fsec(–x) = (–1)x Fsec(x).
- Fcsc(–x) = (–1)x+1 Fcsc(x), for x ≠ 0
There are addition, subtraction, and double-argument formulas (the formulas for Fcot only apply where the indicated function values are defined, of course):
- Ftan(x ± y) =
(Ftan(x) ± Ftan(y)) / (1 ± 5 Ftan(x) Ftan(y)) - Fcot(x ± y) =
(5 ± Fcot(x) Fcot(y)) / (Fcot(x) ± Fcot(y)) - Ftan(2x) = 2 Ftan(x) / (1 + 5 Ftan(x)2)
- Fcot(2x) = (5 + Fcot(x)2) / (2 Fcot(x))
No comments:
Post a Comment