Tuesday, July 27, 2010

FT3: The Basic Analogies


This is the third in a series of posts on Fibonacci trigonometry:








 
In part 2, we gave the following closed-form expressions for the Fibonacci numbers and the Lucas numbers:
  • F(n) = (φn – (–φ)–n)/√5
  • L(n) = φn + (–φ)–n
(Recall that φ represents the golden ratio (1 + √5)/2 = 1.618....)
Using the formulas above, we can derive the following:
  • L(n) + √5 F(n) = 2 φn
  • L(n) – √5 F(n) = 2 (–φ)–n
The four formulas above are reminiscent of standard formulas relating the trigonometric and hyperbolic functions to the exponential function:
F(n) = (φn – (–φ)–n)/√5
L(n) = φn + (–φ)–n

L(n) + √5 F(n) = 2 φn
L(n) – √5 F(n) = 2 (–φ)–n
sin x = (eixe–ix)/2i
cos x = (eix + e–ix)/2
 

cos x + i sin x = eix
cos xi sin x = eix
sinh x = (exe–x)/2
cosh x = (ex + e–x)/2

cosh x + sinh x = ex
cosh x – sinh x = ex

  Because of these similarities, the Fibonacci and Lucas numbers obey many identities similar to well-known trigonometric and hyperbolic identities, as we'll see.
In fact, as we'll see in part 5, there are formulas for F(n) and L(n) in terms of sinh and cosh: F(n) and L(n) are constant multiples of sinh(nψ) and cosh(nψ), respectively, with the proper choice of ψ.





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